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(x^2)-2x=2.5
We move all terms to the left:
(x^2)-2x-(2.5)=0
We add all the numbers together, and all the variables
x^2-2x-2.5=0
a = 1; b = -2; c = -2.5;
Δ = b2-4ac
Δ = -22-4·1·(-2.5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{14}}{2*1}=\frac{2-\sqrt{14}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{14}}{2*1}=\frac{2+\sqrt{14}}{2} $
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